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31759941149 is a prime number
BaseRepresentation
bin11101100101000010…
…100011111000011101
310000222101221011202122
4131211002203320131
51010021021104044
622331301432325
72203020021416
oct354502437035
9100871834678
1031759941149
1112518727952
1261a440b6a5
132cc1b9a8b1
14177409480d
15c5d3bcdee
hex7650a3e1d

31759941149 has 2 divisors, whose sum is σ = 31759941150. Its totient is φ = 31759941148.

The previous prime is 31759941091. The next prime is 31759941197. The reversal of 31759941149 is 94114995713.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31673320900 + 86620249 = 177970^2 + 9307^2 .

It is a cyclic number.

It is not a de Polignac number, because 31759941149 - 28 = 31759940893 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31759941149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31759241149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15879970574 + 15879970575.

It is an arithmetic number, because the mean of its divisors is an integer number (15879970575).

Almost surely, 231759941149 is an apocalyptic number.

It is an amenable number.

31759941149 is a deficient number, since it is larger than the sum of its proper divisors (1).

31759941149 is an equidigital number, since it uses as much as digits as its factorization.

31759941149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1224720, while the sum is 53.

The spelling of 31759941149 in words is "thirty-one billion, seven hundred fifty-nine million, nine hundred forty-one thousand, one hundred forty-nine".