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32000012000023 is a prime number
BaseRepresentation
bin1110100011010100101010…
…10110010001101100010111
311012022011121212010021101111
413101222111112101230113
513143242011033000043
6152020334053235451
76511632062033614
oct721522526215427
9135264555107344
1032000012000023
11a218146598711
123709997332b87
1314b1785315612
147c8b4768150b
153a75d8d7709d
hex1d1a95591b17

32000012000023 has 2 divisors, whose sum is σ = 32000012000024. Its totient is φ = 32000012000022.

The previous prime is 32000011999961. The next prime is 32000012000093. The reversal of 32000012000023 is 32000021000023.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 32000012000023 - 221 = 32000009902871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32000011999967 and 32000012000012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32000012000093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16000006000011 + 16000006000012.

It is an arithmetic number, because the mean of its divisors is an integer number (16000006000012).

Almost surely, 232000012000023 is an apocalyptic number.

32000012000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

32000012000023 is an equidigital number, since it uses as much as digits as its factorization.

32000012000023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 13.

Adding to 32000012000023 its reverse (32000021000023), we get a palindrome (64000033000046).

Subtracting 32000012000023 from its reverse (32000021000023), we obtain a square (9000000 = 30002).

The spelling of 32000012000023 in words is "thirty-two trillion, twelve million, twenty-three", and thus it is an aban number and an uban number.