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320034241141 is a prime number
BaseRepresentation
bin1001010100000111000…
…01101111101001110101
31010121001201212221000021
410222003201233221311
520220412231204031
6403004404245141
732056514110546
oct4520341575165
91117051787007
10320034241141
111137a8a9318a
12520369a07b1
1324243634a74
14116bdbbc4cd
1584d1440511
hex4a8386fa75

320034241141 has 2 divisors, whose sum is σ = 320034241142. Its totient is φ = 320034241140.

The previous prime is 320034241019. The next prime is 320034241157. The reversal of 320034241141 is 141142430023.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 179397990916 + 140636250225 = 423554^2 + 375015^2 .

It is a cyclic number.

It is not a de Polignac number, because 320034241141 - 213 = 320034232949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (320034221141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160017120570 + 160017120571.

It is an arithmetic number, because the mean of its divisors is an integer number (160017120571).

Almost surely, 2320034241141 is an apocalyptic number.

It is an amenable number.

320034241141 is a deficient number, since it is larger than the sum of its proper divisors (1).

320034241141 is an equidigital number, since it uses as much as digits as its factorization.

320034241141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 320034241141 its reverse (141142430023), we get a palindrome (461176671164).

The spelling of 320034241141 in words is "three hundred twenty billion, thirty-four million, two hundred forty-one thousand, one hundred forty-one".