Base | Representation |
---|---|
bin | 101110100101011100010… |
… | …110010110110100000001 |
3 | 102100001010002201210200201 |
4 | 232211130112112310001 |
5 | 404422230300000001 |
6 | 10450353521045201 |
7 | 450200125011415 |
oct | 56453426266401 |
9 | 12301102653621 |
10 | 3201300000001 |
11 | 1024733435144 |
12 | 438524a86801 |
13 | 1a2b5c28703c |
14 | b0d2d8d8d45 |
15 | 58416da8501 |
hex | 2e95c596d01 |
3201300000001 has 2 divisors, whose sum is σ = 3201300000002. Its totient is φ = 3201300000000.
The previous prime is 3201299999981. The next prime is 3201300000011. The reversal of 3201300000001 is 1000000031023.
It is an a-pointer prime, because the next prime (3201300000011) can be obtained adding 3201300000001 to its sum of digits (10).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3154264800625 + 47035199376 = 1776025^2 + 216876^2 .
It is a cyclic number.
It is not a de Polignac number, because 3201300000001 - 27 = 3201299999873 is a prime.
It is not a weakly prime, because it can be changed into another prime (3201300000011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600650000000 + 1600650000001.
It is an arithmetic number, because the mean of its divisors is an integer number (1600650000001).
Almost surely, 23201300000001 is an apocalyptic number.
It is an amenable number.
3201300000001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3201300000001 is an equidigital number, since it uses as much as digits as its factorization.
3201300000001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 10.
Adding to 3201300000001 its reverse (1000000031023), we get a palindrome (4201300031024).
The spelling of 3201300000001 in words is "three trillion, two hundred one billion, three hundred million, one", and thus it is an aban number.
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