Search a number
-
+
320133411151 is a prime number
BaseRepresentation
bin1001010100010010111…
…00000011000101001111
31010121022122111021200121
410222021130003011033
520221113123124101
6403022310005411
732062130045131
oct4521134030517
91117278437617
10320133411151
11113849a68074
1252064046867
132425b047848
14116cd035051
1584d9ece0a1
hex4a8970314f

320133411151 has 2 divisors, whose sum is σ = 320133411152. Its totient is φ = 320133411150.

The previous prime is 320133411137. The next prime is 320133411179. The reversal of 320133411151 is 151114331023.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 320133411151 - 213 = 320133402959 is a prime.

It is a super-2 number, since 2×3201334111512 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (320133411251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160066705575 + 160066705576.

It is an arithmetic number, because the mean of its divisors is an integer number (160066705576).

Almost surely, 2320133411151 is an apocalyptic number.

320133411151 is a deficient number, since it is larger than the sum of its proper divisors (1).

320133411151 is an equidigital number, since it uses as much as digits as its factorization.

320133411151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 320133411151 its reverse (151114331023), we get a palindrome (471247742174).

The spelling of 320133411151 in words is "three hundred twenty billion, one hundred thirty-three million, four hundred eleven thousand, one hundred fifty-one".