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3206014117 is a prime number
BaseRepresentation
bin1011111100010111…
…1110010010100101
322021102200101120121
42333011332102211
523031214422432
61250044001541
7142306445635
oct27705762245
98242611517
103206014117
1113a5790949
127558302b1
133c1296097
14225b126c5
1513b6da197
hexbf17e4a5

3206014117 has 2 divisors, whose sum is σ = 3206014118. Its totient is φ = 3206014116.

The previous prime is 3206014111. The next prime is 3206014169. The reversal of 3206014117 is 7114106023.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3154619556 + 51394561 = 56166^2 + 7169^2 .

It is an emirp because it is prime and its reverse (7114106023) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3206014117 - 23 = 3206014109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3206014091 and 3206014100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3206014111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1603007058 + 1603007059.

It is an arithmetic number, because the mean of its divisors is an integer number (1603007059).

Almost surely, 23206014117 is an apocalyptic number.

It is an amenable number.

3206014117 is a deficient number, since it is larger than the sum of its proper divisors (1).

3206014117 is an equidigital number, since it uses as much as digits as its factorization.

3206014117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 3206014117 is about 56621.6753284464. The cubic root of 3206014117 is about 1474.5351965701.

The spelling of 3206014117 in words is "three billion, two hundred six million, fourteen thousand, one hundred seventeen".