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32111244312143 is a prime number
BaseRepresentation
bin1110100110100011110110…
…10011110111111001001111
311012200210201211100012012012
413103101323103313321033
513202102312020442033
6152143411343531435
76522650366061023
oct723217323677117
9135623654305165
1032111244312143
11a260336304097
12372745a8b9b7b
1314bc100c0b199
147d029a3a6383
153aa44923e248
hex1d347b4f7e4f

32111244312143 has 2 divisors, whose sum is σ = 32111244312144. Its totient is φ = 32111244312142.

The previous prime is 32111244312083. The next prime is 32111244312197. The reversal of 32111244312143 is 34121344211123.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32111244312143 - 216 = 32111244246607 is a prime.

It is a super-2 number, since 2×321112443121432 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32111244312643) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16055622156071 + 16055622156072.

It is an arithmetic number, because the mean of its divisors is an integer number (16055622156072).

Almost surely, 232111244312143 is an apocalyptic number.

32111244312143 is a deficient number, since it is larger than the sum of its proper divisors (1).

32111244312143 is an equidigital number, since it uses as much as digits as its factorization.

32111244312143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 32.

Adding to 32111244312143 its reverse (34121344211123), we get a palindrome (66232588523266).

The spelling of 32111244312143 in words is "thirty-two trillion, one hundred eleven billion, two hundred forty-four million, three hundred twelve thousand, one hundred forty-three".