321112521450041 has 2 divisors, whose sum is σ = 321112521450042. Its totient is φ = 321112521450040.

The previous prime is 321112521449959. The next prime is 321112521450043. The reversal of 321112521450041 is 140054125211123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 218178895974400 + 102933625475641 = 14770880^2 + 10145621^2 .

It is a cyclic number.

It is not a de Polignac number, because 321112521450041 - 2¹⁴ = 321112521433657 is a prime.

It is a super-2 number, since 2×321112521450041² (a number of 30 digits) contains 22 as substring.

Together with 321112521450043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (321112521450043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160556260725020 + 160556260725021.

It is an arithmetic number, because the mean of its divisors is an integer number (160556260725021).

Almost surely, 2^{321112521450041} is an apocalyptic number.

It is an amenable number.

321112521450041 is a deficient number, since it is larger than the sum of its proper divisors (1).

321112521450041 is an equidigital number, since it uses as much as digits as its factorization.

321112521450041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 32.

Adding to 321112521450041 its reverse (140054125211123), we get a palindrome (461166646661164).

The spelling of 321112521450041 in words is "three hundred twenty-one trillion, one hundred twelve billion, five hundred twenty-one million, four hundred fifty thousand, forty-one".