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3211343442949 is a prime number
BaseRepresentation
bin101110101110110010111…
…111000011010000000101
3102101000001001020120100011
4232232302333003100011
5410103312410133244
610455134254550221
7451004040611245
oct56566277032005
912330031216304
103211343442949
111028a17721514
1243a468508371
131a3a9cc751a5
14b1603729b25
1558803998434
hex2ebb2fc3405

3211343442949 has 2 divisors, whose sum is σ = 3211343442950. Its totient is φ = 3211343442948.

The previous prime is 3211343442929. The next prime is 3211343443043. The reversal of 3211343442949 is 9492443431123.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3004873170849 + 206470272100 = 1733457^2 + 454390^2 .

It is an emirp because it is prime and its reverse (9492443431123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3211343442949 - 217 = 3211343311877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3211343442929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1605671721474 + 1605671721475.

It is an arithmetic number, because the mean of its divisors is an integer number (1605671721475).

Almost surely, 23211343442949 is an apocalyptic number.

It is an amenable number.

3211343442949 is a deficient number, since it is larger than the sum of its proper divisors (1).

3211343442949 is an equidigital number, since it uses as much as digits as its factorization.

3211343442949 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2239488, while the sum is 49.

The spelling of 3211343442949 in words is "three trillion, two hundred eleven billion, three hundred forty-three million, four hundred forty-two thousand, nine hundred forty-nine".