Base | Representation |
---|---|
bin | 100100100001001000001001… |
… | …0111001010000000010000011 |
3 | 1120010022121011122022120012021 |
4 | 1021002100102321100002003 |
5 | 314100220323232143021 |
6 | 3055054524025542311 |
7 | 124441553002220215 |
oct | 11102202271200203 |
9 | 1503277148276167 |
10 | 321212331131011 |
11 | 93391425a31911 |
12 | 30039127944997 |
13 | 10a30267915878 |
14 | 5946a8cb945b5 |
15 | 272070ac5dc41 |
hex | 1242412e50083 |
321212331131011 has 2 divisors, whose sum is σ = 321212331131012. Its totient is φ = 321212331131010.
The previous prime is 321212331131009. The next prime is 321212331131033. The reversal of 321212331131011 is 110131133212123.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 321212331131011 - 21 = 321212331131009 is a prime.
Together with 321212331131009, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (321212331138011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160606165565505 + 160606165565506.
It is an arithmetic number, because the mean of its divisors is an integer number (160606165565506).
Almost surely, 2321212331131011 is an apocalyptic number.
321212331131011 is a deficient number, since it is larger than the sum of its proper divisors (1).
321212331131011 is an equidigital number, since it uses as much as digits as its factorization.
321212331131011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 321212331131011 its reverse (110131133212123), we get a palindrome (431343464343134).
The spelling of 321212331131011 in words is "three hundred twenty-one trillion, two hundred twelve billion, three hundred thirty-one million, one hundred thirty-one thousand, eleven".
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