Base | Representation |
---|---|
bin | 1110100110111000001000… |
… | …01101010111110010110111 |
3 | 11012201211211112121022011201 |
4 | 13103130010031113302313 |
5 | 13202242111020132413 |
6 | 152152411523513331 |
7 | 6523514231423653 |
oct | 723340415276267 |
9 | 135654745538151 |
10 | 32122131020983 |
11 | a264a125a2623 |
12 | 3729598828847 |
13 | 14c014751a433 |
14 | 7d0a101c5a63 |
15 | 3aa884da09dd |
hex | 1d3704357cb7 |
32122131020983 has 2 divisors, whose sum is σ = 32122131020984. Its totient is φ = 32122131020982.
The previous prime is 32122131020981. The next prime is 32122131021017. The reversal of 32122131020983 is 38902013122123.
It is a weak prime.
It is an emirp because it is prime and its reverse (38902013122123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32122131020983 - 21 = 32122131020981 is a prime.
Together with 32122131020981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32122131020981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16061065510491 + 16061065510492.
It is an arithmetic number, because the mean of its divisors is an integer number (16061065510492).
Almost surely, 232122131020983 is an apocalyptic number.
32122131020983 is a deficient number, since it is larger than the sum of its proper divisors (1).
32122131020983 is an equidigital number, since it uses as much as digits as its factorization.
32122131020983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 37.
The spelling of 32122131020983 in words is "thirty-two trillion, one hundred twenty-two billion, one hundred thirty-one million, twenty thousand, nine hundred eighty-three".
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