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3212534135093 is a prime number
BaseRepresentation
bin101110101111111001111…
…101001011100100110101
3102101010010000201222220012
4232233321331023210311
5410113232214310333
610455452351350005
7451045406412023
oct56577175134465
912333100658805
103212534135093
111029478850108
1243a73b222305
131a3c2c85ab5a
14b16b7915713
1558873295e48
hex2ebf9f4b935

3212534135093 has 2 divisors, whose sum is σ = 3212534135094. Its totient is φ = 3212534135092.

The previous prime is 3212534135081. The next prime is 3212534135119. The reversal of 3212534135093 is 3905314352123.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3206309240689 + 6224894404 = 1790617^2 + 78898^2 .

It is an emirp because it is prime and its reverse (3905314352123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3212534135093 - 214 = 3212534118709 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3212534135093.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3212534135053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606267067546 + 1606267067547.

It is an arithmetic number, because the mean of its divisors is an integer number (1606267067547).

Almost surely, 23212534135093 is an apocalyptic number.

It is an amenable number.

3212534135093 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212534135093 is an equidigital number, since it uses as much as digits as its factorization.

3212534135093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 291600, while the sum is 41.

The spelling of 3212534135093 in words is "three trillion, two hundred twelve billion, five hundred thirty-four million, one hundred thirty-five thousand, ninety-three".