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3212741032409 is a prime number
BaseRepresentation
bin101110110000000110010…
…010011011100111011001
3102101010122110001110122202
4232300012102123213121
5410114143201014114
610455525102055545
7451053501124136
oct56600622334731
912333573043582
103212741032409
111029574614127
1243a79857a5b5
131a3c6368b6bc
14b16d71b158d
1558886513cde
hex2ec0649b9d9

3212741032409 has 2 divisors, whose sum is σ = 3212741032410. Its totient is φ = 3212741032408.

The previous prime is 3212741032393. The next prime is 3212741032411. The reversal of 3212741032409 is 9042301472123.

3212741032409 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2002734432400 + 1210006600009 = 1415180^2 + 1100003^2 .

It is an emirp because it is prime and its reverse (9042301472123) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3212741032409 - 24 = 3212741032393 is a prime.

Together with 3212741032411, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3212741037409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606370516204 + 1606370516205.

It is an arithmetic number, because the mean of its divisors is an integer number (1606370516205).

Almost surely, 23212741032409 is an apocalyptic number.

It is an amenable number.

3212741032409 is a deficient number, since it is larger than the sum of its proper divisors (1).

3212741032409 is an equidigital number, since it uses as much as digits as its factorization.

3212741032409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 38.

The spelling of 3212741032409 in words is "three trillion, two hundred twelve billion, seven hundred forty-one million, thirty-two thousand, four hundred nine".