Base | Representation |
---|---|
bin | 1110100111000111000010… |
… | …00111001001001010011111 |
3 | 11012202121111011002020221121 |
4 | 13103203201013021022133 |
5 | 13202410002310321343 |
6 | 152200213503111411 |
7 | 6524216424562624 |
oct | 723434107111237 |
9 | 135677434066847 |
10 | 32130132120223 |
11 | a268348a50935 |
12 | 372b0502a2567 |
13 | 14c0b21056997 |
14 | 7d116ca9834b |
15 | 3aaba2516aed |
hex | 1d38e11c929f |
32130132120223 has 2 divisors, whose sum is σ = 32130132120224. Its totient is φ = 32130132120222.
The previous prime is 32130132120173. The next prime is 32130132120259. The reversal of 32130132120223 is 32202123103123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32130132120223 - 225 = 32130098565791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32130132120283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065066060111 + 16065066060112.
It is an arithmetic number, because the mean of its divisors is an integer number (16065066060112).
Almost surely, 232130132120223 is an apocalyptic number.
32130132120223 is a deficient number, since it is larger than the sum of its proper divisors (1).
32130132120223 is an equidigital number, since it uses as much as digits as its factorization.
32130132120223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 32130132120223 its reverse (32202123103123), we get a palindrome (64332255223346).
The spelling of 32130132120223 in words is "thirty-two trillion, one hundred thirty billion, one hundred thirty-two million, one hundred twenty thousand, two hundred twenty-three".
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