Base | Representation |
---|---|
bin | 1110100111001000110111… |
… | …00001001000110111111111 |
3 | 11012202201000102220222120012 |
4 | 13103210123201020313333 |
5 | 13202414004133411221 |
6 | 152200455025413435 |
7 | 6524252623541033 |
oct | 723443341106777 |
9 | 135681012828505 |
10 | 32131112013311 |
11 | a268801091033 |
12 | 372b28449a27b |
13 | 14c0c49073b8c |
14 | 7d1222c901c3 |
15 | 3aac0d57565b |
hex | 1d391b848dff |
32131112013311 has 2 divisors, whose sum is σ = 32131112013312. Its totient is φ = 32131112013310.
The previous prime is 32131112013307. The next prime is 32131112013313. The reversal of 32131112013311 is 11331021113123.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32131112013311 - 22 = 32131112013307 is a prime.
Together with 32131112013313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32131112013313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16065556006655 + 16065556006656.
It is an arithmetic number, because the mean of its divisors is an integer number (16065556006656).
Almost surely, 232131112013311 is an apocalyptic number.
32131112013311 is a deficient number, since it is larger than the sum of its proper divisors (1).
32131112013311 is an equidigital number, since it uses as much as digits as its factorization.
32131112013311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 32131112013311 its reverse (11331021113123), we get a palindrome (43462133126434).
The spelling of 32131112013311 in words is "thirty-two trillion, one hundred thirty-one billion, one hundred twelve million, thirteen thousand, three hundred eleven".
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