Base | Representation |
---|---|
bin | 101110110000011101100… |
… | …100000110010111100100 |
3 | 102101011122122212022021122 |
4 | 232300131210012113210 |
5 | 410120443133234230 |
6 | 10500031532033112 |
7 | 451066252312100 |
oct | 56603544062744 |
9 | 12334578768248 |
10 | 3213131539940 |
11 | 1029754a96223 |
12 | 43a887302798 |
13 | 1a3cc655844a |
14 | b1732dc4900 |
15 | 588aa94ebe5 |
hex | 2ec1d9065e4 |
3213131539940 has 72 divisors (see below), whose sum is σ = 7977897241272. Its totient is φ = 1083585323520.
The previous prime is 3213131539939. The next prime is 3213131540011. The reversal of 3213131539940 is 499351313123.
It can be written as a sum of positive squares in 4 ways, for example, as 348995014564 + 2864136525376 = 590758^2 + 1692376^2 .
It is a junction number, because it is equal to n+sod(n) for n = 3213131539891 and 3213131539900.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26814857 + ... + 26934416.
It is an arithmetic number, because the mean of its divisors is an integer number (110804128351).
Almost surely, 23213131539940 is an apocalyptic number.
It is an amenable number.
3213131539940 is an abundant number, since it is smaller than the sum of its proper divisors (4764765701332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3213131539940 is a wasteful number, since it uses less digits than its factorization.
3213131539940 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53749357 (or 53749348 counting only the distinct ones).
The product of its (nonzero) digits is 262440, while the sum is 44.
The spelling of 3213131539940 in words is "three trillion, two hundred thirteen billion, one hundred thirty-one million, five hundred thirty-nine thousand, nine hundred forty".
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