Base | Representation |
---|---|
bin | 1011111110000100… |
… | …1000000011110011 |
3 | 22021221002000111121 |
4 | 2333201020003303 |
5 | 23040030211034 |
6 | 1250500323111 |
7 | 142424112556 |
oct | 27741100363 |
9 | 8257060447 |
10 | 3213132019 |
11 | 13a9802709 |
12 | 7580a3497 |
13 | 3c28b8b66 |
14 | 226a4669d |
15 | 13c1441b4 |
hex | bf8480f3 |
3213132019 has 2 divisors, whose sum is σ = 3213132020. Its totient is φ = 3213132018.
The previous prime is 3213132007. The next prime is 3213132079. The reversal of 3213132019 is 9102313123.
3213132019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3213132019 - 27 = 3213131891 is a prime.
It is a super-2 number, since 2×32131320192 = 20648434743046032722, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3213131984 and 3213132002.
It is not a weakly prime, because it can be changed into another prime (3213132079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1606566009 + 1606566010.
It is an arithmetic number, because the mean of its divisors is an integer number (1606566010).
Almost surely, 23213132019 is an apocalyptic number.
3213132019 is a deficient number, since it is larger than the sum of its proper divisors (1).
3213132019 is an equidigital number, since it uses as much as digits as its factorization.
3213132019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The square root of 3213132019 is about 56684.4954021821. The cubic root of 3213132019 is about 1475.6256304511.
The spelling of 3213132019 in words is "three billion, two hundred thirteen million, one hundred thirty-two thousand, nineteen".
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