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321323132113 is a prime number
BaseRepresentation
bin1001010110100000101…
…10011110010011010001
31010201101120011101000221
410223100112132103101
520231032210211423
6403340325513041
732133454362304
oct4532026362321
91121346141027
10321323132113
111142aa593035
1252336572781
13243ba680449
14117a304ab3b
158559688e5d
hex4ad059e4d1

321323132113 has 2 divisors, whose sum is σ = 321323132114. Its totient is φ = 321323132112.

The previous prime is 321323132111. The next prime is 321323132131. The reversal of 321323132113 is 311231323123.

Together with next prime (321323132131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 318013661329 + 3309470784 = 563927^2 + 57528^2 .

It is a cyclic number.

It is not a de Polignac number, because 321323132113 - 21 = 321323132111 is a prime.

Together with 321323132111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (321323132111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160661566056 + 160661566057.

It is an arithmetic number, because the mean of its divisors is an integer number (160661566057).

Almost surely, 2321323132113 is an apocalyptic number.

It is an amenable number.

321323132113 is a deficient number, since it is larger than the sum of its proper divisors (1).

321323132113 is an equidigital number, since it uses as much as digits as its factorization.

321323132113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1944, while the sum is 25.

Adding to 321323132113 its reverse (311231323123), we get a palindrome (632554455236).

The spelling of 321323132113 in words is "three hundred twenty-one billion, three hundred twenty-three million, one hundred thirty-two thousand, one hundred thirteen".