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32134141132277 is a prime number
BaseRepresentation
bin1110100111001110100000…
…00100010011110111110101
311012202222211112202011121112
413103213100010103313311
513202441210112213102
6152202115354124405
76524420654612462
oct723472004236765
9135688745664545
1032134141132277
11a26a015a2aa38
12372b98aa20705
1314c130c7b2372
147d142d2b6669
153aad3946c252
hex1d39d0113df5

32134141132277 has 2 divisors, whose sum is σ = 32134141132278. Its totient is φ = 32134141132276.

The previous prime is 32134141132243. The next prime is 32134141132279. The reversal of 32134141132277 is 77223114143123.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26239534982116 + 5894606150161 = 5122454^2 + 2427881^2 .

It is a cyclic number.

It is not a de Polignac number, because 32134141132277 - 212 = 32134141128181 is a prime.

It is a super-2 number, since 2×321341411322772 (a number of 28 digits) contains 22 as substring.

Together with 32134141132279, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32134141132279) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16067070566138 + 16067070566139.

It is an arithmetic number, because the mean of its divisors is an integer number (16067070566139).

Almost surely, 232134141132277 is an apocalyptic number.

It is an amenable number.

32134141132277 is a deficient number, since it is larger than the sum of its proper divisors (1).

32134141132277 is an equidigital number, since it uses as much as digits as its factorization.

32134141132277 is an evil number, because the sum of its binary digits is even.

The product of its digits is 169344, while the sum is 41.

The spelling of 32134141132277 in words is "thirty-two trillion, one hundred thirty-four billion, one hundred forty-one million, one hundred thirty-two thousand, two hundred seventy-seven".