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3214040155453 is a prime number
BaseRepresentation
bin101110110001010011101…
…110001100010100111101
3102101020222222120202110001
4232301103232030110331
5410124323234433303
610500302030514301
7451130624362651
oct56612356142475
912336888522401
103214040155453
11102a080972536
1243aa9b665991
131a410c87a46a
14b17bb944a61
15589105ce31d
hex2ec53b8c53d

3214040155453 has 2 divisors, whose sum is σ = 3214040155454. Its totient is φ = 3214040155452.

The previous prime is 3214040155451. The next prime is 3214040155499. The reversal of 3214040155453 is 3545510404123.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2669782798809 + 544257356644 = 1633947^2 + 737738^2 .

It is a cyclic number.

It is not a de Polignac number, because 3214040155453 - 21 = 3214040155451 is a prime.

Together with 3214040155451, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3214040155451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607020077726 + 1607020077727.

It is an arithmetic number, because the mean of its divisors is an integer number (1607020077727).

Almost surely, 23214040155453 is an apocalyptic number.

It is an amenable number.

3214040155453 is a deficient number, since it is larger than the sum of its proper divisors (1).

3214040155453 is an equidigital number, since it uses as much as digits as its factorization.

3214040155453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 3214040155453 its reverse (3545510404123), we get a palindrome (6759550559576).

The spelling of 3214040155453 in words is "three trillion, two hundred fourteen billion, forty million, one hundred fifty-five thousand, four hundred fifty-three".