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3214441414319 is a prime number
BaseRepresentation
bin101110110001101011101…
…000110111111010101111
3102101022000221121211010112
4232301223220313322233
5410131134000224234
610500405523130235
7451143566126612
oct56615350677257
912338027554115
103214441414319
11102a267418233
1243ab91b1397b
131a4174a3ca45
14b1818d56179
1558935940ace
hex2ec6ba37eaf

3214441414319 has 2 divisors, whose sum is σ = 3214441414320. Its totient is φ = 3214441414318.

The previous prime is 3214441414307. The next prime is 3214441414321. The reversal of 3214441414319 is 9134141444123.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3214441414319 is a prime.

It is a super-2 number, since 2×32144414143192 (a number of 26 digits) contains 22 as substring.

Together with 3214441414321, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3214441414369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1607220707159 + 1607220707160.

It is an arithmetic number, because the mean of its divisors is an integer number (1607220707160).

Almost surely, 23214441414319 is an apocalyptic number.

3214441414319 is a deficient number, since it is larger than the sum of its proper divisors (1).

3214441414319 is an equidigital number, since it uses as much as digits as its factorization.

3214441414319 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 165888, while the sum is 41.

The spelling of 3214441414319 in words is "three trillion, two hundred fourteen billion, four hundred forty-one million, four hundred fourteen thousand, three hundred nineteen".