Base | Representation |
---|---|
bin | 11101111101001000… |
… | …101111000111010001 |
3 | 10002000120122022202121 |
4 | 131331020233013101 |
5 | 1011333014310301 |
6 | 22435342414241 |
7 | 2216026205221 |
oct | 357510570721 |
9 | 102016568677 |
10 | 32164213201 |
11 | 1270595048a |
12 | 6297891381 |
13 | 3057876823 |
14 | 17b1a4c081 |
15 | c83b273a1 |
hex | 77d22f1d1 |
32164213201 has 2 divisors, whose sum is σ = 32164213202. Its totient is φ = 32164213200.
The previous prime is 32164213199. The next prime is 32164213243. The reversal of 32164213201 is 10231246123.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20829416976 + 11334796225 = 144324^2 + 106465^2 .
It is a cyclic number.
It is not a de Polignac number, because 32164213201 - 21 = 32164213199 is a prime.
It is a super-2 number, since 2×321642132012 (a number of 22 digits) contains 22 as substring.
Together with 32164213199, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (32164213271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16082106600 + 16082106601.
It is an arithmetic number, because the mean of its divisors is an integer number (16082106601).
Almost surely, 232164213201 is an apocalyptic number.
It is an amenable number.
32164213201 is a deficient number, since it is larger than the sum of its proper divisors (1).
32164213201 is an equidigital number, since it uses as much as digits as its factorization.
32164213201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 32164213201 its reverse (10231246123), we get a palindrome (42395459324).
The spelling of 32164213201 in words is "thirty-two billion, one hundred sixty-four million, two hundred thirteen thousand, two hundred one".
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