Base | Representation |
---|---|
bin | 1110101001100000000101… |
… | …10001000011010100001111 |
3 | 11020001110120122120121012202 |
4 | 13110300002301003110033 |
5 | 13210231243042224241 |
6 | 152302043222152115 |
7 | 6533155564634063 |
oct | 724600261032417 |
9 | 136043518517182 |
10 | 32212301133071 |
11 | a29a184242414 |
12 | 3742b6258263b |
13 | 14c87b7660a47 |
14 | 7d5125925aa3 |
15 | 3acdb1130d9b |
hex | 1d4c02c4350f |
32212301133071 has 2 divisors, whose sum is σ = 32212301133072. Its totient is φ = 32212301133070.
The previous prime is 32212301133037. The next prime is 32212301133073. The reversal of 32212301133071 is 17033110321223.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32212301133071 - 214 = 32212301116687 is a prime.
Together with 32212301133073, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32212301133073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16106150566535 + 16106150566536.
It is an arithmetic number, because the mean of its divisors is an integer number (16106150566536).
Almost surely, 232212301133071 is an apocalyptic number.
32212301133071 is a deficient number, since it is larger than the sum of its proper divisors (1).
32212301133071 is an equidigital number, since it uses as much as digits as its factorization.
32212301133071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536, while the sum is 29.
Adding to 32212301133071 its reverse (17033110321223), we get a palindrome (49245411454294).
The spelling of 32212301133071 in words is "thirty-two trillion, two hundred twelve billion, three hundred one million, one hundred thirty-three thousand, seventy-one".
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