Base | Representation |
---|---|
bin | 1110101001100011010000… |
… | …00111001011001100101100 |
3 | 11020001121222010222200221201 |
4 | 13110301220013023030230 |
5 | 13210243233331300330 |
6 | 152302524041335244 |
7 | 6533245662140641 |
oct | 724615007131454 |
9 | 136047863880851 |
10 | 32214001431340 |
11 | a29a976a996a3 |
12 | 3743357a97524 |
13 | 14c89c89b2cb1 |
14 | 7d5247687dc8 |
15 | 3ace60542eca |
hex | 1d4c681cb32c |
32214001431340 has 48 divisors (see below), whose sum is σ = 68796971228160. Its totient is φ = 12667022297280.
The previous prime is 32214001431301. The next prime is 32214001431341. The reversal of 32214001431340 is 4313410041223.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 32214001431299 and 32214001431308.
It is not an unprimeable number, because it can be changed into a prime (32214001431341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 110905939 + ... + 111196021.
It is an arithmetic number, because the mean of its divisors is an integer number (1433270233920).
Almost surely, 232214001431340 is an apocalyptic number.
It is an amenable number.
32214001431340 is an abundant number, since it is smaller than the sum of its proper divisors (36582969796820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
32214001431340 is a wasteful number, since it uses less digits than its factorization.
32214001431340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 384262 (or 384260 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 32214001431340 its reverse (4313410041223), we get a palindrome (36527411472563).
The spelling of 32214001431340 in words is "thirty-two trillion, two hundred fourteen billion, one million, four hundred thirty-one thousand, three hundred forty".
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