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32231314412471 is a prime number
BaseRepresentation
bin1110101010000011100000…
…00010111101001110110111
311020010021122201102021021002
413111001300002331032313
513211034212442144341
6152314510022513515
76534431006065406
oct725016002751667
9136107581367232
1032231314412471
11a2a7250798669
123746789b9589b
1314ca52779a925
147d600ab5963d
153ad62544029b
hex1d50700bd3b7

32231314412471 has 2 divisors, whose sum is σ = 32231314412472. Its totient is φ = 32231314412470.

The previous prime is 32231314412413. The next prime is 32231314412519. The reversal of 32231314412471 is 17421441313223.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 32231314412471 - 218 = 32231314150327 is a prime.

It is a super-3 number, since 3×322313144124713 (a number of 42 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32231314414471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16115657206235 + 16115657206236.

It is an arithmetic number, because the mean of its divisors is an integer number (16115657206236).

Almost surely, 232231314412471 is an apocalyptic number.

32231314412471 is a deficient number, since it is larger than the sum of its proper divisors (1).

32231314412471 is an equidigital number, since it uses as much as digits as its factorization.

32231314412471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96768, while the sum is 38.

Adding to 32231314412471 its reverse (17421441313223), we get a palindrome (49652755725694).

The spelling of 32231314412471 in words is "thirty-two trillion, two hundred thirty-one billion, three hundred fourteen million, four hundred twelve thousand, four hundred seventy-one".