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32241011317 is a prime number
BaseRepresentation
bin11110000001101101…
…101100101001110101
310002012221011001222021
4132001231230221311
51012012144330232
622451124433141
72220651034354
oct360155545165
9102187131867
1032241011317
1112745234aa9
1262b95487b1
13306a7556b8
1417bbd1d99b
15c8a747397
hex781b6ca75

32241011317 has 2 divisors, whose sum is σ = 32241011318. Its totient is φ = 32241011316.

The previous prime is 32241011311. The next prime is 32241011347. The reversal of 32241011317 is 71311014223.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30114049156 + 2126962161 = 173534^2 + 46119^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-32241011317 is a prime.

It is a super-4 number, since 4×322410113174 (a number of 43 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 32241011291 and 32241011300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32241011311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16120505658 + 16120505659.

It is an arithmetic number, because the mean of its divisors is an integer number (16120505659).

Almost surely, 232241011317 is an apocalyptic number.

It is an amenable number.

32241011317 is a deficient number, since it is larger than the sum of its proper divisors (1).

32241011317 is an equidigital number, since it uses as much as digits as its factorization.

32241011317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

The spelling of 32241011317 in words is "thirty-two billion, two hundred forty-one million, eleven thousand, three hundred seventeen".