Search a number
-
+
32244051130 = 2517189670889
BaseRepresentation
bin11110000001111001…
…010010110010111010
310002020010212111210221
4132001321102302322
51012013434114010
622451313530254
72221015624654
oct360171226272
9102203774727
1032244051130
1112746a20945
1262ba57398a
13306b27b1c5
1417bc4b16d4
15c8ab47dda
hex781e52cba

32244051130 has 16 divisors (see below), whose sum is σ = 61453368360. Its totient is φ = 12138936832.

The previous prime is 32244051107. The next prime is 32244051139. The reversal of 32244051130 is 3115044223.

It can be written as a sum of positive squares in 4 ways, for example, as 30783053401 + 1460997729 = 175451^2 + 38223^2 .

It is a super-3 number, since 3×322440511303 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 32244051095 and 32244051104.

It is not an unprimeable number, because it can be changed into a prime (32244051139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94835275 + ... + 94835614.

Almost surely, 232244051130 is an apocalyptic number.

32244051130 is a deficient number, since it is larger than the sum of its proper divisors (29209317230).

32244051130 is a wasteful number, since it uses less digits than its factorization.

32244051130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 189670913.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 32244051130 its reverse (3115044223), we get a palindrome (35359095353).

The spelling of 32244051130 in words is "thirty-two billion, two hundred forty-four million, fifty-one thousand, one hundred thirty".

Divisors: 1 2 5 10 17 34 85 170 189670889 379341778 948354445 1896708890 3224405113 6448810226 16122025565 32244051130