Base | Representation |
---|---|
bin | 1100000000111111… |
… | …1011011110000111 |
3 | 22022210011100200120 |
4 | 3000033323132013 |
5 | 23101200314343 |
6 | 1252015313023 |
7 | 142633313052 |
oct | 30017733607 |
9 | 8283140616 |
10 | 3225401223 |
11 | 1405722750 |
12 | 76021b773 |
13 | 3c52c3545 |
14 | 22851ba99 |
15 | 13d269683 |
hex | c03fb787 |
3225401223 has 32 divisors (see below), whose sum is σ = 4771963392. Its totient is φ = 1921536000.
The previous prime is 3225401219. The next prime is 3225401237. The reversal of 3225401223 is 3221045223.
It is not a de Polignac number, because 3225401223 - 22 = 3225401219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3225401193 and 3225401202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3225401323) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 480015 + ... + 486687.
It is an arithmetic number, because the mean of its divisors is an integer number (149123856).
Almost surely, 23225401223 is an apocalyptic number.
3225401223 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3225401223 is a deficient number, since it is larger than the sum of its proper divisors (1546562169).
3225401223 is a wasteful number, since it uses less digits than its factorization.
3225401223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6935.
The product of its (nonzero) digits is 2880, while the sum is 24.
The square root of 3225401223 is about 56792.6159196774. The cubic root of 3225401223 is about 1477.5014488607.
Adding to 3225401223 its reverse (3221045223), we get a palindrome (6446446446).
The spelling of 3225401223 in words is "three billion, two hundred twenty-five million, four hundred one thousand, two hundred twenty-three".
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