Base | Representation |
---|---|
bin | 101111000000011110110… |
… | …110011101100111000010 |
3 | 102102211001110110000121210 |
4 | 233000132312131213002 |
5 | 410411210222001010 |
6 | 10511554451030550 |
7 | 452245443311565 |
oct | 57003666354702 |
9 | 12384043400553 |
10 | 3230333000130 |
11 | 1035a81844925 |
12 | 442087b9b456 |
13 | 1a58081c7662 |
14 | b24c57464dc |
15 | 59065b6db20 |
hex | 2f01ed9d9c2 |
3230333000130 has 128 divisors (see below), whose sum is σ = 7864786575360. Its totient is φ = 849073155840.
The previous prime is 3230333000047. The next prime is 3230333000143. The reversal of 3230333000130 is 310003330323.
It is a junction number, because it is equal to n+sod(n) for n = 3230333000097 and 3230333000106.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 556279687 + ... + 556285493.
It is an arithmetic number, because the mean of its divisors is an integer number (61443645120).
Almost surely, 23230333000130 is an apocalyptic number.
3230333000130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3230333000130 is an abundant number, since it is smaller than the sum of its proper divisors (4634453575230).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3230333000130 is a wasteful number, since it uses less digits than its factorization.
3230333000130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6784.
The product of its (nonzero) digits is 1458, while the sum is 21.
Adding to 3230333000130 its reverse (310003330323), we get a palindrome (3540336330453).
The spelling of 3230333000130 in words is "three trillion, two hundred thirty billion, three hundred thirty-three million, one hundred thirty", and thus it is an aban number.
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