Base | Representation |
---|---|
bin | 100100101111000010011011… |
… | …1010011011011110001001011 |
3 | 1120101002101001020110002202121 |
4 | 1021132010313103123301023 |
5 | 314323031331304440243 |
6 | 3103121113114512111 |
7 | 125026644650105512 |
oct | 11136046723336113 |
9 | 1511071036402677 |
10 | 323124202421323 |
11 | 93a59228488726 |
12 | 302a7775735637 |
13 | 10b3b634c48934 |
14 | 59b141b099679 |
15 | 2755306ceb1ed |
hex | 125e1374dbc4b |
323124202421323 has 2 divisors, whose sum is σ = 323124202421324. Its totient is φ = 323124202421322.
The previous prime is 323124202421291. The next prime is 323124202421333.
It is a happy number.
323124202421323 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 323124202421323 - 25 = 323124202421291 is a prime.
It is a super-2 number, since 2×3231242024213232 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (323124202421333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161562101210661 + 161562101210662.
It is an arithmetic number, because the mean of its divisors is an integer number (161562101210662).
Almost surely, 2323124202421323 is an apocalyptic number.
323124202421323 is a deficient number, since it is larger than the sum of its proper divisors (1).
323124202421323 is an equidigital number, since it uses as much as digits as its factorization.
323124202421323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 34.
It can be divided in two parts, 32312420 and 2421323, that added together give a palindrome (34733743).
The spelling of 323124202421323 in words is "three hundred twenty-three trillion, one hundred twenty-four billion, two hundred two million, four hundred twenty-one thousand, three hundred twenty-three".
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