Base | Representation |
---|---|
bin | 101111000010000011100… |
… | …001111111001000011111 |
3 | 102102222102011211202212221 |
4 | 233002003201333020133 |
5 | 410423140131144411 |
6 | 10512434231010211 |
7 | 452335343555215 |
oct | 57020341771037 |
9 | 12388364752787 |
10 | 3232022131231 |
11 | 1036769264043 |
12 | 442479809967 |
13 | 1a5a17139a0a |
14 | b2605bdccb5 |
15 | 591140c7071 |
hex | 2f08387f21f |
3232022131231 has 2 divisors, whose sum is σ = 3232022131232. Its totient is φ = 3232022131230.
The previous prime is 3232022131199. The next prime is 3232022131243. The reversal of 3232022131231 is 1321312202323.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3232022131231 - 25 = 3232022131199 is a prime.
It is a super-2 number, since 2×32320221312312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3232022131196 and 3232022131205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3232022131271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1616011065615 + 1616011065616.
It is an arithmetic number, because the mean of its divisors is an integer number (1616011065616).
Almost surely, 23232022131231 is an apocalyptic number.
3232022131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
3232022131231 is an equidigital number, since it uses as much as digits as its factorization.
3232022131231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 3232022131231 its reverse (1321312202323), we get a palindrome (4553334333554).
The spelling of 3232022131231 in words is "three trillion, two hundred thirty-two billion, twenty-two million, one hundred thirty-one thousand, two hundred thirty-one".
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