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323213202120197 is a prime number
BaseRepresentation
bin100100101111101011111000…
…0000110010101111000000101
31120101101212202210002020201002
41021133113300012111320011
5314331011114220321242
63103230032323143045
7125036245312055324
oct11137276006257005
91511355683066632
10323213202120197
1193a92a4949a774
1230300a73514a85
1310b46b4975694c
1459b58611ac0bb
1527577b5437432
hex125f5f0195e05

323213202120197 has 2 divisors, whose sum is σ = 323213202120198. Its totient is φ = 323213202120196.

The previous prime is 323213202120139. The next prime is 323213202120269. The reversal of 323213202120197 is 791021202312323.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 267806482662436 + 55406719457761 = 16364794^2 + 7443569^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-323213202120197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 323213202120197.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (323213202120097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161606601060098 + 161606601060099.

It is an arithmetic number, because the mean of its divisors is an integer number (161606601060099).

Almost surely, 2323213202120197 is an apocalyptic number.

It is an amenable number.

323213202120197 is a deficient number, since it is larger than the sum of its proper divisors (1).

323213202120197 is an equidigital number, since it uses as much as digits as its factorization.

323213202120197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 38.

The spelling of 323213202120197 in words is "three hundred twenty-three trillion, two hundred thirteen billion, two hundred two million, one hundred twenty thousand, one hundred ninety-seven".