Base | Representation |
---|---|
bin | 101111000011000110111… |
… | …100110111011110101000 |
3 | 102110002100000020121211121 |
4 | 233003012330313132220 |
5 | 410432444213014430 |
6 | 10513142354505024 |
7 | 452405360123203 |
oct | 57030674673650 |
9 | 12402300217747 |
10 | 3233153251240 |
11 | 10371997a4270 |
12 | 442734595174 |
13 | 1a5b675953b3 |
14 | b26b211c93a |
15 | 5917d558a7a |
hex | 2f0c6f377a8 |
3233153251240 has 64 divisors (see below), whose sum is σ = 7936228368000. Its totient is φ = 1175646647040.
The previous prime is 3233153251219. The next prime is 3233153251243. The reversal of 3233153251240 is 421523513323.
It is a junction number, because it is equal to n+sod(n) for n = 3233153251196 and 3233153251205.
It is not an unprimeable number, because it can be changed into a prime (3233153251243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12539541 + ... + 12794779.
It is an arithmetic number, because the mean of its divisors is an integer number (124003568250).
Almost surely, 23233153251240 is an apocalyptic number.
It is an amenable number.
3233153251240 is an abundant number, since it is smaller than the sum of its proper divisors (4703075116760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3233153251240 is a wasteful number, since it uses less digits than its factorization.
3233153251240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 284050 (or 284046 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 3233153251240 its reverse (421523513323), we get a palindrome (3654676764563).
The spelling of 3233153251240 in words is "three trillion, two hundred thirty-three billion, one hundred fifty-three million, two hundred fifty-one thousand, two hundred forty".
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