Base | Representation |
---|---|
bin | 1110101101001111110100… |
… | …00100111010111010110101 |
3 | 11020111202210012102020010202 |
4 | 13112213322010322322311 |
5 | 13214333334104143433 |
6 | 152441130255130245 |
7 | 6545363144232665 |
oct | 726477204727265 |
9 | 136452705366122 |
10 | 32341004365493 |
11 | a3398199218aa |
12 | 3763aa0b13985 |
13 | 150798898c985 |
14 | 7db454ab21a5 |
15 | 3b13e51e1ee8 |
hex | 1d69fa13aeb5 |
32341004365493 has 2 divisors, whose sum is σ = 32341004365494. Its totient is φ = 32341004365492.
The previous prime is 32341004365451. The next prime is 32341004365531. The reversal of 32341004365493 is 39456340014323.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31783356854929 + 557647510564 = 5637673^2 + 746758^2 .
It is a cyclic number.
It is not a de Polignac number, because 32341004365493 - 28 = 32341004365237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32341004365403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16170502182746 + 16170502182747.
It is an arithmetic number, because the mean of its divisors is an integer number (16170502182747).
Almost surely, 232341004365493 is an apocalyptic number.
It is an amenable number.
32341004365493 is a deficient number, since it is larger than the sum of its proper divisors (1).
32341004365493 is an equidigital number, since it uses as much as digits as its factorization.
32341004365493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2799360, while the sum is 47.
The spelling of 32341004365493 in words is "thirty-two trillion, three hundred forty-one billion, four million, three hundred sixty-five thousand, four hundred ninety-three".
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