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323412121141 is a prime number
BaseRepresentation
bin1001011010011001101…
…11010101011000110101
31010220210010222000020221
410231030313111120311
520244322000334031
6404323512054341
732236311446314
oct4551467253065
91126703860227
10323412121141
1111518179044a
125281a0943b1
13246613b4525
141192066c27b
15862cc78a11
hex4b4cdd5635

323412121141 has 2 divisors, whose sum is σ = 323412121142. Its totient is φ = 323412121140.

The previous prime is 323412121121. The next prime is 323412121159. The reversal of 323412121141 is 141121214323.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 220082018641 + 103330102500 = 469129^2 + 321450^2 .

It is a cyclic number.

It is not a de Polignac number, because 323412121141 - 213 = 323412112949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (323412121121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161706060570 + 161706060571.

It is an arithmetic number, because the mean of its divisors is an integer number (161706060571).

Almost surely, 2323412121141 is an apocalyptic number.

It is an amenable number.

323412121141 is a deficient number, since it is larger than the sum of its proper divisors (1).

323412121141 is an equidigital number, since it uses as much as digits as its factorization.

323412121141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 25.

Adding to 323412121141 its reverse (141121214323), we get a palindrome (464533335464).

The spelling of 323412121141 in words is "three hundred twenty-three billion, four hundred twelve million, one hundred twenty-one thousand, one hundred forty-one".