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32450004133 is a prime number
BaseRepresentation
bin11110001110001010…
…111100010010100101
310002202111102000012221
4132032022330102211
51012424200113013
622523552112341
72226066325021
oct361612742245
9102674360187
1032450004133
11128421aa438
1263575356b1
1330a1b3aca1
1417db9a3381
15c9dc7b08d
hex78e2bc4a5

32450004133 has 2 divisors, whose sum is σ = 32450004134. Its totient is φ = 32450004132.

The previous prime is 32450004109. The next prime is 32450004149. The reversal of 32450004133 is 33140005423.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28310754564 + 4139249569 = 168258^2 + 64337^2 .

It is a cyclic number.

It is not a de Polignac number, because 32450004133 - 217 = 32449873061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 32450004098 and 32450004107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32450004173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16225002066 + 16225002067.

It is an arithmetic number, because the mean of its divisors is an integer number (16225002067).

Almost surely, 232450004133 is an apocalyptic number.

It is an amenable number.

32450004133 is a deficient number, since it is larger than the sum of its proper divisors (1).

32450004133 is an equidigital number, since it uses as much as digits as its factorization.

32450004133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 32450004133 its reverse (33140005423), we get a palindrome (65590009556).

The spelling of 32450004133 in words is "thirty-two billion, four hundred fifty million, four thousand, one hundred thirty-three".