Base | Representation |
---|---|
bin | 11110001110001010… |
… | …111100010010100101 |
3 | 10002202111102000012221 |
4 | 132032022330102211 |
5 | 1012424200113013 |
6 | 22523552112341 |
7 | 2226066325021 |
oct | 361612742245 |
9 | 102674360187 |
10 | 32450004133 |
11 | 128421aa438 |
12 | 63575356b1 |
13 | 30a1b3aca1 |
14 | 17db9a3381 |
15 | c9dc7b08d |
hex | 78e2bc4a5 |
32450004133 has 2 divisors, whose sum is σ = 32450004134. Its totient is φ = 32450004132.
The previous prime is 32450004109. The next prime is 32450004149. The reversal of 32450004133 is 33140005423.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28310754564 + 4139249569 = 168258^2 + 64337^2 .
It is a cyclic number.
It is not a de Polignac number, because 32450004133 - 217 = 32449873061 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32450004098 and 32450004107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32450004173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16225002066 + 16225002067.
It is an arithmetic number, because the mean of its divisors is an integer number (16225002067).
Almost surely, 232450004133 is an apocalyptic number.
It is an amenable number.
32450004133 is a deficient number, since it is larger than the sum of its proper divisors (1).
32450004133 is an equidigital number, since it uses as much as digits as its factorization.
32450004133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 32450004133 its reverse (33140005423), we get a palindrome (65590009556).
The spelling of 32450004133 in words is "thirty-two billion, four hundred fifty million, four thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •