Base | Representation |
---|---|
bin | 100100111101100000000101… |
… | …0100010110011010000100110 |
3 | 1120122010101221202102112221102 |
4 | 1021323000022202303100212 |
5 | 320103113404430124110 |
6 | 3111242222320520102 |
7 | 125323365652056611 |
oct | 11173001242632046 |
9 | 1518111852375842 |
10 | 325112021333030 |
11 | 94655263431598 |
12 | 30568a7a180032 |
13 | 10c53c16983149 |
14 | 5a3d711c6d178 |
15 | 278bd9a6d75a5 |
hex | 127b00a8b3426 |
325112021333030 has 64 divisors (see below), whose sum is σ = 604331307606528. Its totient is φ = 125797285370880.
The previous prime is 325112021332993. The next prime is 325112021333093. The reversal of 325112021333030 is 30333120211523.
It is a super-3 number, since 3×3251120213330303 (a number of 45 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 325112021332984 and 325112021333002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8565252812 + ... + 8565290768.
It is an arithmetic number, because the mean of its divisors is an integer number (9442676681352).
Almost surely, 2325112021333030 is an apocalyptic number.
325112021333030 is a deficient number, since it is larger than the sum of its proper divisors (279219286273498).
325112021333030 is a wasteful number, since it uses less digits than its factorization.
325112021333030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48801.
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 325112021333030 its reverse (30333120211523), we get a palindrome (355445141544553).
The spelling of 325112021333030 in words is "three hundred twenty-five trillion, one hundred twelve billion, twenty-one million, three hundred thirty-three thousand, thirty".
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