Base | Representation |
---|---|
bin | 1001011101101000000… |
… | …11101000111001110111 |
3 | 1011002020210200002110012 |
4 | 10232310003220321313 |
5 | 20311343202300210 |
6 | 405211355250435 |
7 | 32330233204565 |
oct | 4566403507167 |
9 | 1132223602405 |
10 | 325143400055 |
11 | 11598aa77971 |
12 | 53021a49a1b |
13 | 24878c92c16 |
14 | 11a46576a35 |
15 | 86cec5a305 |
hex | 4bb40e8e77 |
325143400055 has 32 divisors (see below), whose sum is σ = 398318679360. Its totient is φ = 254745169920.
The previous prime is 325143400033. The next prime is 325143400063. The reversal of 325143400055 is 550004341523.
It is a happy number.
It is not a de Polignac number, because 325143400055 - 222 = 325139205751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 325143399994 and 325143400030.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 55472825 + ... + 55478685.
It is an arithmetic number, because the mean of its divisors is an integer number (12447458730).
Almost surely, 2325143400055 is an apocalyptic number.
325143400055 is a deficient number, since it is larger than the sum of its proper divisors (73175279305).
325143400055 is a wasteful number, since it uses less digits than its factorization.
325143400055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7139.
The product of its (nonzero) digits is 36000, while the sum is 32.
Adding to 325143400055 its reverse (550004341523), we get a palindrome (875147741578).
The spelling of 325143400055 in words is "three hundred twenty-five billion, one hundred forty-three million, four hundred thousand, fifty-five".
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