Base | Representation |
---|---|
bin | 100100111110011100101000… |
… | …1000110011111100010100111 |
3 | 1120122120211120222001012211202 |
4 | 1021330321101012133202213 |
5 | 320112231211323112242 |
6 | 3111422045330353115 |
7 | 125335651204342652 |
oct | 11174712106374247 |
9 | 1518524528035752 |
10 | 325242054113447 |
11 | 946a5420560079 |
12 | 3058a109a2b79b |
13 | 10c6326a594373 |
14 | 5a45b2982c899 |
15 | 279045b373932 |
hex | 127ce5119f8a7 |
325242054113447 has 2 divisors, whose sum is σ = 325242054113448. Its totient is φ = 325242054113446.
The previous prime is 325242054113227. The next prime is 325242054113489. The reversal of 325242054113447 is 744311450242523.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 325242054113447 - 214 = 325242054097063 is a prime.
It is a super-2 number, since 2×3252420541134472 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (325242054112447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162621027056723 + 162621027056724.
It is an arithmetic number, because the mean of its divisors is an integer number (162621027056724).
Almost surely, 2325242054113447 is an apocalyptic number.
325242054113447 is a deficient number, since it is larger than the sum of its proper divisors (1).
325242054113447 is an equidigital number, since it uses as much as digits as its factorization.
325242054113447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3225600, while the sum is 47.
The spelling of 325242054113447 in words is "three hundred twenty-five trillion, two hundred forty-two billion, fifty-four million, one hundred thirteen thousand, four hundred forty-seven".
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