Base | Representation |
---|---|
bin | 1110110010111011110011… |
… | …10110110100011101011110 |
3 | 11021012110012011120102022111 |
4 | 13121131321312310131132 |
5 | 13231034042422242430 |
6 | 153111005322304234 |
7 | 6565451601062533 |
oct | 731357166643536 |
9 | 137173164512274 |
10 | 32536421680990 |
11 | a4046898a8337 |
12 | 379593995807a |
13 | 152022c7450c6 |
14 | 806ab22c2d8a |
15 | 3b6531193c2a |
hex | 1d9779db475e |
32536421680990 has 32 divisors (see below), whose sum is σ = 59085184086720. Its totient is φ = 12899101684224.
The previous prime is 32536421680957. The next prime is 32536421681107. The reversal of 32536421680990 is 9908612463523.
It is a super-3 number, since 3×325364216809903 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53163951 + ... + 53772469.
It is an arithmetic number, because the mean of its divisors is an integer number (1846412002710).
Almost surely, 232536421680990 is an apocalyptic number.
32536421680990 is a deficient number, since it is larger than the sum of its proper divisors (26548762405730).
32536421680990 is a wasteful number, since it uses less digits than its factorization.
32536421680990 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 655956.
The product of its (nonzero) digits is 16796160, while the sum is 58.
The spelling of 32536421680990 in words is "thirty-two trillion, five hundred thirty-six billion, four hundred twenty-one million, six hundred eighty thousand, nine hundred ninety".
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