Base | Representation |
---|---|
bin | 101111010111001101101… |
… | …001000101001100101110 |
3 | 102112011001110011102200221 |
4 | 233113031221011030232 |
5 | 411311202011412200 |
6 | 10531112421041554 |
7 | 454101333301435 |
oct | 57271551051456 |
9 | 12464043142627 |
10 | 3254740341550 |
11 | 1045367087775 |
12 | 446959b562ba |
13 | 1a7bc7a05a09 |
14 | b375d0d811c |
15 | 599e37c391a |
hex | 2f5cda4532e |
3254740341550 has 48 divisors (see below), whose sum is σ = 6195462139152. Its totient is φ = 1271443219200.
The previous prime is 3254740341511. The next prime is 3254740341577. The reversal of 3254740341550 is 551430474523.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a junction number, because it is equal to n+sod(n) for n = 3254740341497 and 3254740341506.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15982972 + ... + 16185328.
It is an arithmetic number, because the mean of its divisors is an integer number (129072127899).
Almost surely, 23254740341550 is an apocalyptic number.
3254740341550 is a deficient number, since it is larger than the sum of its proper divisors (2940721797602).
3254740341550 is a wasteful number, since it uses less digits than its factorization.
3254740341550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 209893 (or 209888 counting only the distinct ones).
The product of its (nonzero) digits is 1008000, while the sum is 43.
The spelling of 3254740341550 in words is "three trillion, two hundred fifty-four billion, seven hundred forty million, three hundred forty-one thousand, five hundred fifty".
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