3257000141 has 2 divisors, whose sum is σ = 3257000142. Its totient is φ = 3257000140.

The previous prime is 3257000101. The next prime is 3257000143. The reversal of 3257000141 is 1410007523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2698386916 + 558613225 = 51946^2 + 23635^2 .

It is a cyclic number.

It is not a de Polignac number, because 3257000141 - 2¹⁴ = 3256983757 is a prime.

Together with 3257000143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3257000143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1628500070 + 1628500071.

It is an arithmetic number, because the mean of its divisors is an integer number (1628500071).

Almost surely, 2^3257000141 is an apocalyptic number.

It is an amenable number.

3257000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3257000141 is an equidigital number, since it uses as much as digits as its factorization.

3257000141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 3257000141 is about 57070.1335288433. The cubic root of 3257000141 is about 1482.3107531237.

Adding to 3257000141 its reverse (1410007523), we get a palindrome (4667007664).

The spelling of 3257000141 in words is "three billion, two hundred fifty-seven million, one hundred forty-one", and thus it is an aban number.