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32848553117 is a prime number
BaseRepresentation
bin11110100101111011…
…010010010010011101
310010210021100101122102
4132211323102102131
51014233212144432
623031310254445
72242006044302
oct364573222235
9103707311572
1032848553117
1112a27174166
126448ab7425
133136591ca3
1418388ab0a9
15cc3c54962
hex7a5ed249d

32848553117 has 2 divisors, whose sum is σ = 32848553118. Its totient is φ = 32848553116.

The previous prime is 32848553107. The next prime is 32848553191. The reversal of 32848553117 is 71135584823.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16706596516 + 16141956601 = 129254^2 + 127051^2 .

It is an emirp because it is prime and its reverse (71135584823) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 32848553117 - 28 = 32848552861 is a prime.

It is a super-3 number, since 3×328485531173 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (32848553107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16424276558 + 16424276559.

It is an arithmetic number, because the mean of its divisors is an integer number (16424276559).

Almost surely, 232848553117 is an apocalyptic number.

It is an amenable number.

32848553117 is a deficient number, since it is larger than the sum of its proper divisors (1).

32848553117 is an equidigital number, since it uses as much as digits as its factorization.

32848553117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 806400, while the sum is 47.

The spelling of 32848553117 in words is "thirty-two billion, eight hundred forty-eight million, five hundred fifty-three thousand, one hundred seventeen".