Base | Representation |
---|---|
bin | 110000000001101001111… |
… | …000001010000011000110 |
3 | 102200111200100210112010010 |
4 | 300001221320022003012 |
5 | 413033014132242410 |
6 | 11004050403011050 |
7 | 460303534304634 |
oct | 60015170120306 |
9 | 12614610715103 |
10 | 3300311212230 |
11 | 106272170536a |
12 | 453757669a86 |
13 | 1ac2aac83b56 |
14 | b5a434ca354 |
15 | 5acae3c8c20 |
hex | 30069e0a0c6 |
3300311212230 has 16 divisors (see below), whose sum is σ = 7920746909424. Its totient is φ = 880082989920.
The previous prime is 3300311212193. The next prime is 3300311212241. The reversal of 3300311212230 is 322121130033.
It is a junction number, because it is equal to n+sod(n) for n = 3300311212197 and 3300311212206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55005186841 + ... + 55005186900.
It is an arithmetic number, because the mean of its divisors is an integer number (495046681839).
Almost surely, 23300311212230 is an apocalyptic number.
3300311212230 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
3300311212230 is an abundant number, since it is smaller than the sum of its proper divisors (4620435697194).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3300311212230 is a wasteful number, since it uses less digits than its factorization.
3300311212230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110010373751.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 3300311212230 its reverse (322121130033), we get a palindrome (3622432342263).
The spelling of 3300311212230 in words is "three trillion, three hundred billion, three hundred eleven million, two hundred twelve thousand, two hundred thirty".
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