Base | Representation |
---|---|
bin | 100101100001010110111001… |
… | …0111100100110001001100011 |
3 | 1121021120112012001122110000122 |
4 | 1023002231302330212021203 |
5 | 321224334111201222201 |
6 | 3125534155022310455 |
7 | 126342416234105366 |
oct | 11302556274461143 |
9 | 1537515161573018 |
10 | 330040100414051 |
11 | 96185247613135 |
12 | 31023b95a2842b |
13 | 11220856653701 |
14 | 5b7005184c0dd |
15 | 2825178d56e1b |
hex | 12c2b72f26263 |
330040100414051 has 2 divisors, whose sum is σ = 330040100414052. Its totient is φ = 330040100414050.
The previous prime is 330040100413981. The next prime is 330040100414053. The reversal of 330040100414051 is 150414001040033.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-330040100414051 is a prime.
Together with 330040100414053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 330040100414051.
It is not a weakly prime, because it can be changed into another prime (330040100414053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165020050207025 + 165020050207026.
It is an arithmetic number, because the mean of its divisors is an integer number (165020050207026).
Almost surely, 2330040100414051 is an apocalyptic number.
330040100414051 is a deficient number, since it is larger than the sum of its proper divisors (1).
330040100414051 is an equidigital number, since it uses as much as digits as its factorization.
330040100414051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 330040100414051 its reverse (150414001040033), we get a palindrome (480454101454084).
The spelling of 330040100414051 in words is "three hundred thirty trillion, forty billion, one hundred million, four hundred fourteen thousand, fifty-one".
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