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330145255541 is a prime number
BaseRepresentation
bin1001100110111100011…
…00001101000001110101
31011120011101112200021002
410303132030031001311
520402114141134131
6411355554333045
732565210240623
oct4633614150165
91146141480232
10330145255541
11118017431a32
1253b98b8a185
132519532121a
1411d9c99c513
1588c3e2b6cb
hex4cde30d075

330145255541 has 2 divisors, whose sum is σ = 330145255542. Its totient is φ = 330145255540.

The previous prime is 330145255537. The next prime is 330145255549. The reversal of 330145255541 is 145552541033.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 280101328516 + 50043927025 = 529246^2 + 223705^2 .

It is a cyclic number.

It is not a de Polignac number, because 330145255541 - 22 = 330145255537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 330145255495 and 330145255504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (330145255549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165072627770 + 165072627771.

It is an arithmetic number, because the mean of its divisors is an integer number (165072627771).

Almost surely, 2330145255541 is an apocalyptic number.

It is an amenable number.

330145255541 is a deficient number, since it is larger than the sum of its proper divisors (1).

330145255541 is an equidigital number, since it uses as much as digits as its factorization.

330145255541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180000, while the sum is 38.

Adding to 330145255541 its reverse (145552541033), we get a palindrome (475697796574).

The spelling of 330145255541 in words is "three hundred thirty billion, one hundred forty-five million, two hundred fifty-five thousand, five hundred forty-one".