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330150654149 is a prime number
BaseRepresentation
bin1001100110111101000…
…00110011000011000101
31011120011202200221202112
410303132200303003011
520402122031413044
6411400310150405
732565304154201
oct4633640630305
91146152627675
10330150654149
1111801a489a98
1253b9a952405
1325196491574
1411d9d5a5b01
1588c464609e
hex4cde8330c5

330150654149 has 2 divisors, whose sum is σ = 330150654150. Its totient is φ = 330150654148.

The previous prime is 330150654109. The next prime is 330150654191. The reversal of 330150654149 is 941456051033.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 327584522500 + 2566131649 = 572350^2 + 50657^2 .

It is an emirp because it is prime and its reverse (941456051033) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 330150654149 - 216 = 330150588613 is a prime.

It is a super-2 number, since 2×3301506541492 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (330150654109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165075327074 + 165075327075.

It is an arithmetic number, because the mean of its divisors is an integer number (165075327075).

Almost surely, 2330150654149 is an apocalyptic number.

It is an amenable number.

330150654149 is a deficient number, since it is larger than the sum of its proper divisors (1).

330150654149 is an equidigital number, since it uses as much as digits as its factorization.

330150654149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 41.

The spelling of 330150654149 in words is "three hundred thirty billion, one hundred fifty million, six hundred fifty-four thousand, one hundred forty-nine".