Search a number
-
+
330212131133 is a prime number
BaseRepresentation
bin1001100111000100010…
…11010100000100111101
31011120100001101022022212
410303202023110010331
520402233301144013
6411410343550205
732566651542323
oct4634213240475
91146301338285
10330212131133
11118051159615
1253bb745b365
13251a6137891
1411da7809d13
1588c9c3b6a8
hex4ce22d413d

330212131133 has 2 divisors, whose sum is σ = 330212131134. Its totient is φ = 330212131132.

The previous prime is 330212131129. The next prime is 330212131159. The reversal of 330212131133 is 331131212033.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 222442403044 + 107769728089 = 471638^2 + 328283^2 .

It is an emirp because it is prime and its reverse (331131212033) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 330212131133 - 22 = 330212131129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 330212131099 and 330212131108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (330212131103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165106065566 + 165106065567.

It is an arithmetic number, because the mean of its divisors is an integer number (165106065567).

Almost surely, 2330212131133 is an apocalyptic number.

It is an amenable number.

330212131133 is a deficient number, since it is larger than the sum of its proper divisors (1).

330212131133 is an equidigital number, since it uses as much as digits as its factorization.

330212131133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 330212131133 its reverse (331131212033), we get a palindrome (661343343166).

The spelling of 330212131133 in words is "three hundred thirty billion, two hundred twelve million, one hundred thirty-one thousand, one hundred thirty-three".