Base | Representation |
---|---|
bin | 1111000001100110100101… |
… | …01000101010100001011111 |
3 | 11022222122002211200110020202 |
4 | 13200303102220222201133 |
5 | 13312313241103104002 |
6 | 154134321021134115 |
7 | 6650043315562412 |
oct | 740632250524137 |
9 | 138878084613222 |
10 | 33040422316127 |
11 | a589401043166 |
12 | 38575566ba33b |
13 | 15589106776b5 |
14 | 823244983b79 |
15 | 3c46cd125502 |
hex | 1e0cd2a2a85f |
33040422316127 has 2 divisors, whose sum is σ = 33040422316128. Its totient is φ = 33040422316126.
The previous prime is 33040422316093. The next prime is 33040422316157. The reversal of 33040422316127 is 72161322404033.
It is a strong prime.
It is an emirp because it is prime and its reverse (72161322404033) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33040422316127 - 212 = 33040422312031 is a prime.
It is a super-2 number, since 2×330404223161272 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33040422316157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16520211158063 + 16520211158064.
It is an arithmetic number, because the mean of its divisors is an integer number (16520211158064).
Almost surely, 233040422316127 is an apocalyptic number.
33040422316127 is a deficient number, since it is larger than the sum of its proper divisors (1).
33040422316127 is an equidigital number, since it uses as much as digits as its factorization.
33040422316127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
The spelling of 33040422316127 in words is "thirty-three trillion, forty billion, four hundred twenty-two million, three hundred sixteen thousand, one hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •