Base | Representation |
---|---|
bin | 100101101000010110011101… |
… | …0000001001111010001100111 |
3 | 1121101222101222222221210022011 |
4 | 1023100230322001033101213 |
5 | 321341110443302112241 |
6 | 3131551505500015051 |
7 | 126502022514610516 |
oct | 11320547201172147 |
9 | 1541871888853264 |
10 | 331001218004071 |
11 | 965159124199aa |
12 | 3115a306231487 |
13 | 11290386268b64 |
14 | 5ba4789cc467d |
15 | 284017bc94281 |
hex | 12d0b3a04f467 |
331001218004071 has 2 divisors, whose sum is σ = 331001218004072. Its totient is φ = 331001218004070.
The previous prime is 331001218004069. The next prime is 331001218004077. The reversal of 331001218004071 is 170400812100133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331001218004071 - 21 = 331001218004069 is a prime.
Together with 331001218004069, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331001218004077) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165500609002035 + 165500609002036.
It is an arithmetic number, because the mean of its divisors is an integer number (165500609002036).
Almost surely, 2331001218004071 is an apocalyptic number.
331001218004071 is a deficient number, since it is larger than the sum of its proper divisors (1).
331001218004071 is an equidigital number, since it uses as much as digits as its factorization.
331001218004071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 31.
The spelling of 331001218004071 in words is "three hundred thirty-one trillion, one billion, two hundred eighteen million, four thousand, seventy-one".
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